If The Magnetic Field Isnã‚’t Changed, What Will Be The Orbital Radius Of The Alpha Particles?
Transcript
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| 00:00 - 00:59 | howdy dear students we are given with the question which is a Proton and an Alpha particle both enters a region of compatible magnetic field b a moving at a right bending to the magnetic field if the radius of round orbit for both particle is equal to radius of round orbit of both particles are equal and the kinetic energy acquired past Proton is 1 Mega electron volt and then we demand to calculate the energy acquired by Blastoff particle so this both the particles are entering a compatible magnetic field and we know that when the charged particle is moving in a compatible magnetic field it experiences a force let's say we have a in word magnetic field equally shown in the effigy hither and there is a charged particle enters in the region so what we can say is past using right hand Palm rule we can decide its direction allow's say for instance discharge is moving perpendicular with the same velocity |
| 01:00 - 01:59 | we are so what will happen this will experience a iv letter did they are also that the magnetic field this charged particle will experience of strength and it volition tend to movement in the round path effectually this circular path must be having some radius alright in the end it has followed the round path it must be having some of the radius associated with it so we can discover the direction of the charged particle by using right mitt Palm rule this is for let's meet if there is some positive accuse + q and everything went wrong in uniform magnetic field by using correct hand Palm dominion finger pointing in the direction of magnetic field and Thumb in the management of velocity and so I will give the management of code that is strength volition be interim in the opposite direction so it will accept a circular path from here nosotros can encounter since it is taking a circular path of a window that this |
| 02:00 - 02:59 | CM postal service will be provided past the magnetic force that is UV b is the magnetic force interim on the charge and this provides the centripetal force that is a square by electropositive are to be the radius of the round path from here we can write are can exist written as Thousand bi bi S cube or it tin exist farther resolved as MB can be written as this is the momentum so we tin can write it has a under root ii inch we have been asked for Canadian we have to convert a Momentum into energy so nosotros will write it has to am kinetic energy Grand / q b and H are nosotros are interested in finding the Canadian energy values for volition take the ke from we volition resolve this equation and will calculate old utilize the value of g wire therefore we can write ke tin be written as |
| 03:00 - 03:59 | Q foursquare b square are square divided by 2 m and so this is what we will observe the value of free energy energy every bit from now hither we can just deduce the relation by using the abiding relation from here we can write kinetic energy of Alpha particle / kinetic free energy of proton will be equal to since they are directly proportional to kinetic energy directly proportional to the charge a probable write it has a few Alpha over so lets it u alphabet q Proton magnetic field is ringtone but know this |
| 04:00 - 04:59 | get cancelled out and radius over again it is straight relation is directly proportional to our Powai are protons square and Masters in US being in changed human relationship will write mass of proton past mass of Alpha particle and it is from here we can calculate K alphabet is Canadian free energy of Alpha particle that will exist get a Proton into you lot Blastoff nosotros are we tin can write your assistance I tin exist written as two times of charge on proton to alphabetical characters charged twice that of charge carried by Proton upwardly into both the radius is been given to exist as equal to this volition again go cancelled out from here and we are left with mass of proton will be as information technology is |
| 05:00 - 05:59 | mass of Blastoff sport and mass of proton from here solving this equation KPS given to be as one into a few people go cancelled out and this is where information technology comes out to be 4 and from here it likewise get cancelled out this will be won the first then nosotros are left it 1 Mega electron volt energy of Blastoff particle is 1 ml in world in this case the right option matching is option d i promise you take understood the concept and thanks for watching |
Source: https://www.doubtnut.com/question-answer-physics/a-proton-and-an-alpha-particle-both-enters-a-region-of-uniform-magnetic-field-b-moving-at-right-angl-643990375
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